题目描述:
Given a string s and a string t, check if s is subsequence of t.
You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace"
is a subsequence of "abcde"
while "aec"
is not).
Example 1:
s = "abc"
, t = "ahbgdc"
Return true
.
Example 2:
s = "axc"
, t = "ahbgdc"
Return false
.
题目大意:
给定字符串s与字符串t,判断s是否是t的子序列。
你可以假设两字符串中都只包含小写字母。t的长度可能会很长(长度 ~= 500,000),s长度较短(<=100)
某字符串的子序列是指从其中删除某些字母(也可以不删除),而剩余字符的相对顺序保持不变,得到的新字符串。(例如,"ace"是"abcde"的子序列,而"aec"则不是)。
解题思路:
利用队列(Queue)数据结构。
将s加入队列,遍历t,当t的当前字符c与队头相同时,将队头弹出。
最后判断队列是否为空即可。
Python代码:
class Solution(object):
def isSubsequence(self, s, t):
"""
:type s: str
:type t: str
:rtype: bool
"""
queue = collections.deque(s)
for c in t:
if not queue: return True
if c == queue[0]:
queue.popleft()
return not queue
本文链接:http://bookshadow.com/weblog/2016/09/04/leetcode-is-subsequence/
请尊重作者的劳动成果,转载请注明出处!书影博客保留对文章的所有权利。