题目描述:
Given a 2D integer matrix M representing the gray scale of an image, you need to design a smoother to make the gray scale of each cell becomes the average gray scale (rounding down) of all the 8 surrounding cells and itself. If a cell has less than 8 surrounding cells, then use as many as you can.
Example 1:
Input: [[1,1,1], [1,0,1], [1,1,1]] Output: [[0, 0, 0], [0, 0, 0], [0, 0, 0]] Explanation: For the point (0,0), (0,2), (2,0), (2,2): floor(3/4) = floor(0.75) = 0 For the point (0,1), (1,0), (1,2), (2,1): floor(5/6) = floor(0.83333333) = 0 For the point (1,1): floor(8/9) = floor(0.88888889) = 0
Note:
- The value in the given matrix is in the range of [0, 255].
- The length and width of the given matrix are in the range of [1, 150].
题目大意:
给定二维矩阵,表示图像的灰度。对图像进行平滑处理,将每一个像素的值换成其周围9个单元格的平均值。
解题思路:
模拟题
Python代码:
class Solution(object):
def imageSmoother(self, M):
"""
:type M: List[List[int]]
:rtype: List[List[int]]
"""
dx, dy = [-1, 0, 1], [-1, 0, 1]
w, h = len(M), len(M[0])
N = []
for x in range(w):
row = []
for y in range(h):
nbs = [M[x + i][y + j] for i in dx for j in dy \
if 0 <= x + i < w and 0 <= y + j < h]
row.append(sum(nbs) / len(nbs))
N.append(row)
return N
本文链接:http://bookshadow.com/weblog/2017/08/21/leetcode-image-smoother/
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