题目描述:
LeetCode 646. Maximum Length of Pair Chain
You are given n
pairs of numbers. In every pair, the first number is always smaller than the second number.
Now, we define a pair (c, d)
can follow another pair (a, b)
if and only if b < c
. Chain of pairs can be formed in this fashion.
Given a set of pairs, find the length longest chain which can be formed. You needn't use up all the given pairs. You can select pairs in any order.
Example 1:
Input: [[1,2], [2,3], [3,4]] Output: 2 Explanation: The longest chain is [1,2] -> [3,4]
Note:
- The number of given pairs will be in the range [1, 1000].
题目大意:
给定一组数对,我们定义当且仅当b < c时,(c, d)可以链在(a, b)之后。求可以组成的最长数对链的长度。
解题思路:
数对根据第二个元素进行排序,一趟遍历。
Python代码:
class Solution(object):
def findLongestChain(self, pairs):
"""
:type pairs: List[List[int]]
:rtype: int
"""
pairs.sort(key = lambda x: x[1])
last = [-0x7FFFFFFF, -0x7FFFFFFF]
ans = 0
for p in pairs:
if p[0] > last[1]:
ans += 1
last = p
return ans
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