题目描述：

LeetCode 794. Valid Tic-Tac-Toe State

A Tic-Tac-Toe board is given as a string array board. Return True if and only if it is possible to reach this board position during the course of a valid tic-tac-toe game.

The board is a 3 x 3 array, and consists of characters " ", "X", and "O".  The " " character represents an empty square.

Here are the rules of Tic-Tac-Toe:

• Players take turns placing characters into empty squares (" ").
• The first player always places "X" characters, while the second player always places "O" characters.
• "X" and "O" characters are always placed into empty squares, never filled ones.
• The game ends when there are 3 of the same (non-empty) character filling any row, column, or diagonal.
• The game also ends if all squares are non-empty.
• No more moves can be played if the game is over.
Example 1:
Input: board = ["O  ", "   ", "   "]
Output: false
Explanation: The first player always plays "X".

Example 2:
Input: board = ["XOX", " X ", "   "]
Output: false
Explanation: Players take turns making moves.

Example 3:
Input: board = ["XXX", "   ", "OOO"]
Output: false

Example 4:
Input: board = ["XOX", "O O", "XOX"]
Output: true

Note:

• board is a length-3 array of strings, where each string board[i] has length 3.
• Each board[i][j] is a character in the set {" ", "X", "O"}.

题目大意：

'X'先'O'后，当三子连珠时（横、竖、对角线）游戏结束。

Python代码：

class Solution(object):
def validTicTacToe(self, board):
"""
:type board: List[str]
:rtype: bool
"""
nx = ''.join(board).count('X')
no = ''.join(board).count('O')
wx, wo = self.isWin(board, 'X'), self.isWin(board, 'O')
if wx: return nx == no + 1 and not wo
if wo: return nx == no
return nx - 1 <= no <= nx

def isWin(self, board, pc):
if any(r == pc * 3 for r in board): return True
if any(c == pc * 3 for c in zip(*board)): return True
if board == board == board == pc: return True
if board == board == board == pc: return True
return False

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