## 题目描述：

LeetCode 806. Number of Lines To Write String

We are to write the letters of a given string `S`, from left to right into lines. Each line has maximum width 100 units, and if writing a letter would cause the width of the line to exceed 100 units, it is written on the next line. We are given an array `widths`, an array where widths[0] is the width of 'a', widths[1] is the width of 'b', ..., and widths[25] is the width of 'z'.

Now answer two questions: how many lines have at least one character from `S`, and what is the width used by the last such line? Return your answer as an integer list of length 2.

```Example :
Input:
widths = [10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10]
S = "abcdefghijklmnopqrstuvwxyz"
Output: [3, 60]
Explanation:
All letters have the same length of 10. To write all 26 letters,
we need two full lines and one line with 60 units.
```
```Example :
Input:
widths = [4,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10,10]
S = "bbbcccdddaaa"
Output: [2, 4]
Explanation:
All letters except 'a' have the same length of 10, and
"bbbcccdddaa" will cover 9 * 10 + 2 * 4 = 98 units.
For the last 'a', it is written on the second line because
there is only 2 units left in the first line.
So the answer is 2 lines, plus 4 units in the second line.
```

Note:

• The length of `S` will be in the range [1, 1000].
• `S` will only contain lowercase letters.
• `widths` is an array of length `26`.
• `widths[i]` will be in the range of `[2, 10]`.

## Python代码：

``````class Solution(object):
def numberOfLines(self, widths, S):
"""
:type widths: List[int]
:type S: str
:rtype: List[int]
"""
lines = cnt = 0
for c in S:
lc = widths[ord(c) - ord('a')]
if cnt + lc > 100:
lines += 1
cnt = lc
else:
cnt += lc
return [lines + (cnt > 0), cnt]
``````

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